MURANG’A SOUTH END OF TERM ONE EXAMINATION, 2025
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MURANG’A SOUTH END OF TERM ONE EXAMINATION, 2025

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MURANG’A SOUTH END OF TERM ONE EXAMINATION, 2025
Kenya Certificate of Secondary Education
121/1
MATHEMATICS
PAPER 1
TIME: 2½ HOURS
SECTION I (50 Marks)
Attempt all the questions in this section
1.
Evaluate;
(3 marks)
−12÷(−3)×4−(−20)
−6×6÷(−6)
2.
3.
4.
5.
6.
a)
b)
7.
8.
9.
Solve the following expressions using substitution method.
(3 marks)
3𝑥 + 4𝑦 = 3
𝑥 + 6𝑦 = 7
Solve for x; 9𝑥 × 27𝑥−1 = 1
(3 marks)
2
2
The surface area of two similar bottles are 12 𝑐𝑚 and 108 𝑐𝑚 respectively. If the larger one has
a volume of 810 𝑐𝑚3 , find the volume of the smaller one.
(3 marks)
Express 0.27 as fraction hence solve 0.27 − 0.14
(3 marks)
The sum of interior angles of a regular polygon is 1 080°
Find the size of each exterior angle.
(2 marks)
Name the polygon.
(1 mark)
Calculate the area of the figure below;

Book Details

Category: Mathematics Exams
Added on: October 04, 2025
Formats: Digital, Print
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